CEMC Cayley, 2008

Number theory Difficulty 3.0 AMC 10/12 Find the answer Canada

Suppose $N = 1 + 11 + 101 + 1001 + 10001 + \ldots + 1\underbrace{000\ldots00}_{50 \text{ zeroes}}1$ . When $N$ is calculated and written as a single integer, the sum of its digits is

(A) $50$ (B) $99$ (C) $55$ (D) $58$ (E) $103$

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