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, 2024 Difficulty 1.2 Junior Find the answer Canada
If $ 1 6 + 1 3 = 1 x \$\dfrac{1}{6} + \dfrac{1}{3} =
\dfrac{1}{x} $ 6 1 + 3 1 = x 1 , t h e v a l u e o f , the value of , t h e v a l u eo f
Pick one
A 9 9 9 B 6 6 6 C 18 18 18 D 2 2 2 E 3 3 3
Solution Simplifying, $ 1 6 + 1 3 = 1 6 + 2 6 = 3 6 = 1 2 \$\dfrac{1}{6} +
\dfrac{1}{3} = \dfrac{1}{6} + \dfrac{2}{6} = \dfrac{3}{6} =
\dfrac{1}{2} $ 6 1 + 3 1 = 6 1 + 6 2 = 6 3 = 2 1 . T h u s , . Thus, . T h u s , 1 x = 1 2 \dfrac{1}{x} =
\dfrac{1}{2} x 1 = 2 1 a n d s o and so an d so
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