Maths Olympiad Prep

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CEMC Cayley, 2024

Algebra Difficulty 1.2 Junior Find the answer Canada

If 16+13=1x\dfrac{1}{6} + \dfrac{1}{3} = \dfrac{1}{x}, the value of xx is

Pick one

Solution

Simplifying, 16+13=16+26=36=12\dfrac{1}{6} + \dfrac{1}{3} = \dfrac{1}{6} + \dfrac{2}{6} = \dfrac{3}{6} = \dfrac{1}{2}. Thus, 1x=12\dfrac{1}{x} = \dfrac{1}{2} and so x=2x = 2.

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