Maths Olympiad Prep

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, 2013

Algebra Difficulty 1.3 Junior Find the answer Canada

An expression that produces the values in the second row of the table shown, given the values of nn in the first row, is

nn
1
2
3
4
5

value
1
3
5
7
9

Pick one

Solution

When n=4n=4, we are looking for an expression that produces a value of 7.
The results of substituting n=4n=4 into each expression and evaluating are shown below.

Expression
Value

(A) 3n23n-2
3(4)2=122=103(4)-2=12-2=10

(B) 2(n1)2(n-1)
2(41)=2(3)=62(4-1)=2(3)=6

(C) n+4n+4
4+4=84+4=8

(D) 2n2n
2(4)=82(4)=8

(E) 2n12n-1
2(4)1=81=72(4)-1=8-1=7

Since 2n12n-1 is the only expression which gives a value of 7 when n=4n=4, it is the only possible answer. We check that the expression 2n12n-1 does give the remaining values, 1,3,5,91,3,5,9, when n=1,2,3,5n=1,2,3,5, respectively.
(Alternately, we may have began by substituting n=1n=1 and noticing that this eliminates answers (B), (C) and (D). Substituting n=2n=2 eliminates (A). Substituting n=3n=3, n=4n=4 and n=5n=5 confirms the answer (E).)

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.