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CEMC Gauss (Grade 7), 2013

Algebra Difficulty 1.3 Junior Find the answer Canada

An expression that produces the values in the second row of the table shown, given the values of nn in the first row, is

nn12345
value13579

Pick one

Solution

When n=4n=4, we are looking for an expression that produces a value of 7.
The results of substituting n=4n=4 into each expression and evaluating are shown below.

ExpressionValue
(A) 3n−23n-23(4)−2=12−2=103(4)-2=12-2=10
(B) 2(n−1)2(n-1)2(4−1)=2(3)=62(4-1)=2(3)=6
(C) n+4n+44+4=84+4=8
(D) 2n2n2(4)=82(4)=8
(E) 2n−12n-12(4)−1=8−1=72(4)-1=8-1=7

Since 2n−12n-1 is the only expression which gives a value of 7 when n=4n=4, it is the only possible answer. We check that the expression 2n−12n-1 does give the remaining values, 1,3,5,91,3,5,9, when n=1,2,3,5n=1,2,3,5, respectively.
(Alternately, we may have began by substituting n=1n=1 and noticing that this eliminates answers (B), (C) and (D). Substituting n=2n=2 eliminates (A). Substituting n=3n=3, n=4n=4 and n=5n=5 confirms the answer (E).)

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