Elina and Gustavo leave Cayley H.S. at 3:00 p.m. Elina runs north at a constant speed of 12 km/h. Gustavo walks east at a constant speed of 5 km/h. After 12 minutes, Elina and Gustavo change direction and travel directly towards each other, still at 12 km/h and 5 km/h, respectively. The time that they will meet again is closest to
, 2021
Pick one
Solution
Elina and Gustavo start by running and walking for 12 minutes.
Since there are 60 minutes in 1 hour, 12 minutes equals of an hour.
When Elina runs at 12 km/h for of an hour, she runs km to the north.
When Gustavo walks at 5 km/h for of an hour, he walks km to the east.
At this point, Elina and Gustavo start to travel directly towards each other.
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As they change direction, we use the Pythagorean Theorem to calculate their distance from each other. Using this, we obtain .
Since Elina continues to travel at 12 km/h, Gustavo continues to travel at 5 km/h, and they travel directly towards each other, they close the gap at a rate of .
Thus, it takes for them to meet.
Since there are 60 minutes in an hour, 0.153 h is equivalent to roughly 9.18 minutes.
Since Elina and Gustavo leave at 3:00 p.m. and travel for 12 minutes and then for an additional 9 minutes, they meet again at approximately 3:21 p.m.