When n=101, which of the following expressions has an even value?
Pick one
Solution
When n=101:
3nn+2n−122n−23n+2=3×101=303=101+2=103=101−12=89=2×101−2=202−2=200=3×101+2=303+2=305. Of the expressions given, 2n−2 is the only expression which has an even value when n=101.
(In fact, the value of 2n−2 is an even integer for every integer n. Can you see why?)
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