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CEMC Cayley, 2015

Geometry Difficulty 2.5 Junior Find the answer Canada

In the diagram, △PQR\triangle PQR is isosceles with PQ=PRPQ=PR and △PRS\triangle PRS is isosceles with PS=SR=xPS=SR=x.
Figure 0
Also, the perimeter of △PQR\triangle PQR is 22, the perimeter of △PRS\triangle PRS is 22, and the perimeter of PQRSPQRS is 24. What is the value of xx?

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Solution

Since PS=SR=xPS=SR=x and the perimeter of △PRS\triangle PRS is 22, then PR=22−PS−SR=22−2xPR=22-PS-SR=22-2x.

Since PQ=PRPQ=PR and PR=22−2xPR=22-2x, then PQ=22−2xPQ=22-2x.

Since △PQR\triangle PQR has perimeter 22, then RQ=22−PR−PQ=22−(22−2x)−(22−2x)=4x−22RQ=22-PR-PQ = 22-(22-2x)-(22-2x)=4x-22.

Figure 1

Since the perimeter of PQRSPQRS is 24, then PQ+RQ+SR+PSamp;=24(22−2x)+(4x−22)+x+xamp;=244xamp;=24xamp;=6\begin{aligned} PQ+RQ+SR+PS & = 24 \\ (22-2x)+(4x-22)+x+x & = 24 \\ 4x & = 24 \\ x & = 6\end{aligned} Therefore, x=6x=6.

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