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Algebra Difficulty 2.0 Junior Find the answer Canada

There are a certain number of red balls, green balls and blue balls in a bag. Of the balls in the bag, $\dfrac{1}{3}$ are red and $\dfrac{2}{7}$ are blue. The number of green balls in the bag is $8$ less than twice the number of blue balls. The number of green balls in the bag is

(A) $12$ (B) $16$ (C) $20$ (D) $24$ (E) $28$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.