Library / /236 of 387

, 2003

Number theory Difficulty 2.0 Junior Find the answer Canada

Let $N = 10^3 + 10^4 + 10^5 + 10^6 + 10^7 + 10^8 + 10^9$ . The sum of the digits of $N$ is

(A) $12$ (B) $1$ (C) $6$ (D) $9$ (E) $7$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.