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Progetto Olimpiadi di Matematica - GARA di SECONDO LIVELLO

Geometry Difficulty 4.3 AIME Find the answer Italy

Problem:

Let ABCABC be a triangle and let A′A' be the reflection of AA with respect to BCBC; let DAA′DAA' be similar to ABCABC and let D′D' be the reflection of DD with respect to AA′AA'. Knowing that the product of the areas of the quadrilaterals ABA′CABA'C and ADA′D′ADA'D' is 1616, can we say that AA′AA' ...

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Solution

Solution:

The answer is (D). Let HH be the foot of the altitude from AA to BCBC, let KK be the foot of the altitude from DD to AA′AA'; the product of the areas of the indicated quadrilaterals is (AH⋅BC)(DK⋅AA′)=16(AH \cdot BC)(DK \cdot AA') = 16. We have the following equalities: AA′=2AHAA' = 2AH by construction and AA′⋅AH=BC⋅DKAA' \cdot AH = BC \cdot DK by similarity between ABCABC and DAA′DAA'. Substituting the second into the product we get AH⋅AA′⋅AH⋅AA′=16AH \cdot AA' \cdot AH \cdot AA' = 16, that is (using the first equality) AA′4=4⋅16=64AA'^4 = 4 \cdot 16 = 64, from which AA′=22AA' = 2\sqrt{2}.

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Source: MathNet, licensed CC-BY-4.0. Statement translated into English from it; metadata (topic, difficulty) added by this project.