To determine the range of slopes for line $l$ that does not intersect with the line segment AB, we first need to calculate the slopes of line segments PA and PB.

The slope of PA, denoted as $k_{PA}$, can be calculated using the formula for the slope between two points, $m = \frac{y_2 - y_1}{x_2 - x_1}$.
$$k_{PA} = \frac{-2 - (-1)}{1 - 0} = \frac{-1}{1} = -1$$

Similarly, for line segment PB:
$$k_{PB} = \frac{1 - (-1)}{2 - 0} = \frac{2}{2} = 1$$

Now, we know that the slopes of lines with a 135° inclination angle and a 45° inclination angle are $-1$ and $1$, respectively.
Since the line $l$ should not intersect the line segment AB, its slope $k$ must satisfy $k > k_{PB}$ or $k < k_{PA}$. This is because the slopes between these values would mean the line would intersect with segment AB at some point.

Therefore, the slope of line $l$ must be greater than $1$ or less than $-1$, and as a result, the inclination angle range for line $l$ is between 45° and 135°, not inclusive.

$$\boxed{(\text{45°, 135°})}$$

Hence, the range of slopes for line $l$ is translated into the range of inclination angles as $(45°,135°)$.