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Problem 331

Number theory Difficulty 2.4 Multiple choice CEMC Fermat · Canada · 2022

Suppose that dd is an odd
integer and ee is an even integer.
How many of the following expressions are equal to an odd integer?

d+dd + d
(e+e)×d(e+e)\times d
d×dd\times d
d×(e+d)d\times(e+d)

Pick one

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Official solution

Since dd is an odd integer,
then d+dd + d is even and d×dd \times d is odd.

Since ee is an even integer, then
e+ee + e is even, which means that
(e+e)×d(e+e) \times d is even.

Also, e+de + d is odd, which means
that d×(e+d)d \times (e+d) is odd.

Thus, 2 of the 4 expressions are equal to an odd integer.

Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty, ordering) added by this project.