Maths Olympiad Prep

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Stage 3 · Number theory

10 problems · AMC 10/12, early questions · mathsolympiadprep.com

The answer key prints on its own page at the end.

  1. For how many integers aa with 1≤a≤101 \leq a \leq 10 is a2014+a2015a^{2014}+a^{2015} divisible by 5?

    CEMC Fermat

    Number theory Solution and answer checking →

  2. For how many pairs (m,n)(m, n) with mm and nn integers satisfying 1≤m≤1001 \leq m \leq 100 and 101≤n≤205101 \leq n \leq 205 is 3m+7n3^{m}+7^{n} divisible by 10?

    CEMC Cayley

    Number theory Solution and answer checking →

  3. For each positive integer nn, define S(n)S(n) to be the smallest positive integer divisible by each of the positive integers 1,2,3,…,n1, 2, 3, \ldots, n. How many positive integers nn with 1≤n≤1001 \leq n \leq 100 have S(n)=S(n+4)S(n) = S(n+4)?

    CEMC Cayley

    Number theory Solution and answer checking →

  4. The integer NN is the smallest positive integer that is a multiple of 2024, has more than 100 positive divisors (including 1 and NN), and has fewer than 110 positive divisors (including 1 and NN). What is the sum of the digits of NN?

    CEMC Fermat

    Number theory Solution and answer checking →

  5. If mm and nn are positive integers with n>1n > 1 such that mn=225×340m^{n} = 2^{25} \times 3^{40}, what is m+nm + n?

    CEMC Fermat

    Number theory Solution and answer checking →

  6. For how many odd integers kk between 0 and 100 does the equation 24m2+2m2−n2+4=2k+4+23m2+n2+k2^{4m^{2}}+2^{m^{2}-n^{2}+4}=2^{k+4}+2^{3m^{2}+n^{2}+k} have exactly two pairs of positive integers (m,n)(m, n) that are solutions?

    CEMC Fermat

    Number theory Solution and answer checking →

  7. There are FF fractions mn\frac{m}{n} with the properties: mm and nn are positive integers with m<nm<n, mn\frac{m}{n} is in lowest terms, nn is not divisible by the square of any integer larger than 1, and the shortest sequence of consecutive digits that repeats consecutively and indefinitely in the decimal equivalent of mn\frac{m}{n} has length 6. We define G=F+pG=F+p, where the integer FF has pp digits. What is the sum of the squares of the digits of GG?

    CEMC Fermat

    Number theory Solution and answer checking →

  8. Teddy has 1010 rectangular
    blocks each of which measures 3 cm\text{3 cm} by 4 cm\text{4 cm} by
    5 cm\text{5 cm}. He builds a stack
    that is exactly 21 cm\text{21 cm} high,
    where each block can be stacked on any of its faces. What is the
    smallest number of blocks that Teddy could use to make this stack?

    1. A44
    2. B55
    3. C66
    4. D77
    5. E88

    CEMC Cayley 2025

    Number theory Solution and answer checking →

  9. Find the remainder when 19171519^{17^{15}} is divided by 100.

    Hong Kong Preliminary Selection Contest

    Number theory Solution and answer checking →

  10. The remainder when 111 is divided by 10 is 1. The remainder when
    111 is divided by the positive integer nn is 6. The number of possible values of
    nn is

    1. A55
    2. B88
    3. C77
    4. D66
    5. E44

    CEMC Fermat 2022

    Number theory Solution and answer checking →

Answer key — Stage 3 · Number theory

Worked solutions for every problem are on the site, one page per problem.

  1. 44 open
  2. 26252625 open
  3. 1111 open
  4. 2727 open
  5. 209957209957 open
  6. 1818 open
  7. 181181 open
  8. BB open
  9. 5959 open
  10. AA open

Problems belong to the competitions that set them. Each question on this sheet names the competition it came from, and the licences the material is used under are listed below. Free to copy for classroom use.

Apache-2.0 · CC-BY-NC-4.0 · CC-BY-4.0